4k^4/3-65k^2/3+16=0

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Solution for 4k^4/3-65k^2/3+16=0 equation: 


k in (-oo:+oo)

(4*k^4)/3-((65*k^2)/3)+16 = 0

(4*k^4)/3+(-65/3)*k^2+16 = 0

4/3*k^4-65/3*k^2+16 = 0

t_1 = k^2

4/3*t_1^2-65/3*t_1^1+16 = 0

4/3*t_1^2-65/3*t_1+16 = 0

DELTA = (-65/3)^2-(4/3*4*16)

DELTA = 3457/9

DELTA > 0

t_1 = ((3457/9)^(1/2)+65/3)/(4/3*2) or t_1 = (65/3-(3457/9)^(1/2))/(4/3*2)

t_1 = 3/8*((3457/9)^(1/2)+65/3) or t_1 = 3/8*(65/3-(3457/9)^(1/2))

t_1 = 3/8*(65/3-(3457/9)^(1/2))

k^2-(3/8*(65/3-(3457/9)^(1/2))) = 0

k^2-3/8*(65/3-(3457/9)^(1/2)) = 0

1*k^2 = -(-3/8*(65/3-(3457/9)^(1/2))) // : 1

k^2 = 3/8*(65/3-(3457/9)^(1/2))

k^2 = 3/8*(65/3-(3457/9)^(1/2)) // ^ 1/2

abs(k) = (3/8)^(1/2)*(65/3-(3457/9)^(1/2))^(1/2)

k = (3/8)^(1/2)*(65/3-(3457/9)^(1/2))^(1/2) or k = -((3/8)^(1/2)*(65/3-(3457/9)^(1/2))^(1/2))

t_1 = 3/8*((3457/9)^(1/2)+65/3)

k^2-(3/8*((3457/9)^(1/2)+65/3)) = 0

k^2-3/8*((3457/9)^(1/2)+65/3) = 0

1*k^2 = -(-3/8*((3457/9)^(1/2)+65/3)) // : 1

k^2 = 3/8*((3457/9)^(1/2)+65/3)

k^2 = 3/8*((3457/9)^(1/2)+65/3) // ^ 1/2

abs(k) = (3/8)^(1/2)*((3457/9)^(1/2)+65/3)^(1/2)

k = (3/8)^(1/2)*((3457/9)^(1/2)+65/3)^(1/2) or k = -((3/8)^(1/2)*((3457/9)^(1/2)+65/3)^(1/2))

k in { (3/8)^(1/2)*(65/3-(3457/9)^(1/2))^(1/2), -((3/8)^(1/2)*(65/3-(3457/9)^(1/2))^(1/2)), (3/8)^(1/2)*((3457/9)^(1/2)+65/3)^(1/2), -((3/8)^(1/2)*((3457/9)^(1/2)+65/3)^(1/2)) }

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